判断当前内容类型的代码
如果当前页面的内容类型符合设定,则返回True:
<?php<br />
$match = FALSE ;<br />
$types = array( 'book' => 1 ); //此处设定内容类型</p>
<p>if (( arg ( 0 ) == 'node' ) && is_numeric ( arg ( 1 ))) {<br />
$node = node_load ( arg ( 1 ));<br />
$match = isset( $types [ $node -> type ]);<br />
}</p>
<p>$match |= (( arg ( 0 ) == 'taxonomy' ) && ( arg ( 1 ) == "term" )); </p>
<p>return $match ;<br />
?>
